Why is the electric field outside the spherical capacitor zero?

Andres Wilkinson asked a question: Why is the electric field outside the spherical capacitor zero?
Asked By: Andres Wilkinson
Date created: Tue, Jun 1, 2021 11:07 AM

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Those who are looking for an answer to the question «Why is the electric field outside the spherical capacitor zero?» often ask the following questions:

👉 Why is the electric field zero outside a capacitor?

Where q1 is the charge producing electric field, and q2 is the charge under cosideration. Hence, electric field is given by: E=F/q2; hence it can be seen that electric field is 0 only when either force between them is zero or the charge which produces the electric field is zero.

👉 Why is the electric field outside a capacitor zero degree?

Because the charge on the two plates is the same magnitude, and of opposite sign, so that the net charge is zero. A spherical capacitor is spherically symmetric, so that the electric field must point radially outward everywhere, and be equal in ma...

👉 Why is the electric field outside a capacitor zero force?

The electric field in the air around a capacitor is small, but not zero. A charged capacitor forms an electric dipole. But importantly for this case, the electric field in the leads of the capacitor become 0 only when the potential difference (voltage) at a capacitor plate is equal to the voltage of the battery terminal it is connected to.

10 other answers

This means also that the electric field at every point on your surface must be zero. Since the radius of the sphere is arbitrary, this means that the electric field at any point outside the capacitor must be zero (as long as no other charged bodies exist in the universe).

Why is the electric field outside the spherical capacitor zero? Because the charge on the two plates is the same magnitude, and of opposite sign, so that the net charge is zero. A spherical capacitor is spherically symmetric, so that the electric field must point radially outward everywhere, and be equal in magnitude.

Using the fact that the electric field is zero outside the capacitor, we can deduce the he flux through a box that encloses only one plate is all through the side of the box that's inside the capacitor. Hence, the electric field must be $4\pi\rho$ inside the capacitor.

The direction of electric field is the same in the direction of electric force. Why is there no electric field at the center of a charged spherical conductor? At the center of a charged spherical conductor, mutual cancellation of forces occurs, resulting in zero net force at the center. So the electric field is zero.

The electric field due to a plate of the capacitor is independent of the distance from it (its uniform) provided its not infinite. So if the finite identical plates have uniform charge density, away from the edges outside the capacitor the field should be 0.

By applying Gauss' lawto an charged conducting sphere, the electric field outside it is found to be The voltage between the spheres can be found by integrating the electric field along a radial line: From the definition of capacitance, the capacitance is Does an isolated charged sphere have capacitance?

1. Just look at the upper Gaussian surface. If the dielectric is inserted with the capacitor disconnected from any voltage source, then the charge on the plates remains unchanged. If the charge inside the upper Gaussian surface is unchanged, then (using Gauss's law and the fact that the E-field is still perpendicular to the plates) the electric ...

It is the + Q and − Q induced charges on the surface of the inner conducting shell which ensure that the electric field inside the conductor is zero. The net charge on that inner shell is + Q + (− Q) = 0. Let r be the distance from the centre. In region A the electric field is 1 4 π ϵ o − Q r 2.

Consider a thick spherical shell with radiuses a, b. Now, let there be a point charge q outside the shell. It is said the the electric field inside the shell is 0 due to the reason above. However, if we move the charge to the center of the shell, it is said that the electric field inside the shell is k q r 2, which is different than 0.

The $\mathbf{E}$ in Gauss's Law is the electric field due to all charges, both inside and outside the Gaussian surface. The reason that charges outside do not contribute to the total surface integral is the field they produce "contributes twice", once when the field "enters" and once when it "leaves" the surface.

Your Answer

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