Why should electric field intensity be perpendicular to the surface of a charged conductor?

Selena Kozey asked a question: Why should electric field intensity be perpendicular to the surface of a charged conductor?
Asked By: Selena Kozey
Date created: Tue, Mar 23, 2021 1:04 AM

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Those who are looking for an answer to the question «Why should electric field intensity be perpendicular to the surface of a charged conductor?» often ask the following questions:

👉 Why electric field is perpendicular to surface of conductor?

Here is another intuitive explanation: Imagine for a moment that the electric field was not perpendicular to the surface. That means it has a component along the surface. Now, electric fields exert a force on charges, so now we have a force on the charges in the conductor along the surface of the conductor.

👉 Why electric field intensity inside a charged conductor is zero?

We know that electric field intensity is defined as the force per unit charge. The electric field intensity inside a charged conductor is zero because there are no electric lines of force within the conductor.

👉 Why is the electric field intensity zero inside a charged conductor?

Electric filed due to uniformly charged spherical shell at a point inside the shell, the total flux crossing the Gaussian sphere normally in an outward direction. there is no charge enclosed by the gaussian surface, according to Gauss law

11 other answers

becos if there is electric field along the tangential line the charges will move to the another place

Here is another intuitive explanation: Imagine for a moment that the electric field was not perpendicular to the surface. That means it has a component along the surface. Now, electric fields exert a force on charges, so now we have a force on the charges in the conductor along the surface of the conductor.

An electric field inside a conductor means that there are electric forces acting to accelerate the charges. Charges within the conductor will accelerate until there are no more electric fields within the conductor. Unless there is some outside source of energy driving the charges, they will quickly migrate to the surface be

Now, suppose electric field lines are not perpendicular to the local surface of the conductor . Then electric field will have some component parallel to the surface. This component will give potential difference d V = − E (p a r a l l e l). d l between the nearby points. Then, the surface is not equipotential surface.

In other words, the charges would move to a new equilibrium position, in which the electric field IS perpendicular to the surface. If it isn't perpendicular, the charges would be redistributed...

The mutual repulsion of excess positive charges on a spherical conductor distributes them uniformly on its surface. The resulting electric field is perpendicular to the surface and zero inside. Outside the conductor, the field is identical to that of a point charge at the center equal to the excess charge.

If a charge is set into motion, then the object upon which it is on is not in a state of electrostatic equilibrium. Therefore, the electric field must be entirely perpendicular to the conducting surface for objects that are at electrostatic equilibrium.

Because the net charge inside a conductor remains zero, the total charge of a conductor resides on its surface, as charges want to attain equilibrium so they come on surface, to minimize the  repulsion among them.As the  charge inside a conductor is zero therefore, if we apply Gauss' theorem to find the electric field inside a conductor, we find it zero.

The net electric field inside a conductor is always zero. So, there is no electric field lines inside a conductor. In this article, I will explain why the net electric field line inside a conductor...

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If the surface is placed in a uniform electric field E A nˆ ur that points in the same direction as nˆ , i.e., perpendicular to the surface A, the flux through the surface is ˆ Φ=E EA⋅=E⋅nA=EA r r r (4.1.1) On the other hand, if the electric fieldE ur makes an angle θ with (Figure 4.1.2), the electric flux becomes nˆ Φ=E EA⋅=EAcosθ=En A r r

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We've handpicked 22 related questions for you, similar to «Why should electric field intensity be perpendicular to the surface of a charged conductor?» so you can surely find the answer!

Is electric field always perpendicular at a surface current?

If electric field was not perpendicular to the surface, that means it has a component along the surface. Since electric field exerts a force on the charges, now we have a force on the charges along the surface. This force isn't balanced, so it will then move charges around i.e, there would be surface currents. So, to avoid that electric field must emanate perpendicular to surfaces.

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Is electric field always perpendicular at a surface due?

Is the other way around, electric fields and equipotential surface are perpendicular always by definition, the charge path (if allowed to move) will follow electric field lines jumping from one equipotential surface to next one, if a charge were to move parallel to a surface that can not be equipotential (charges moves along gradients and there is no gradient within an equipotential surface)

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Is electric field always perpendicular at a surface formula?

Assuming that that electric field is not perpendicular to the surface, then there must be a component of the electric field that is parallel to the surface. Since the electric field is defined to the be gradient of the potential, the surface of the conductor would not have a constant potential.

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Is electric field always perpendicular at a surface plate?

The electric field lines are directed from one plate to the other, and are always perpendicular to the plate surface. This holds good for most electrical devices that depend on the utilization of electric field in real-life applications. 384 views

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Is electric field always perpendicular at a surface point?

Assuming that that electric field is not perpendicular to the surface, then there must be a component of the electric field that is parallel to the surface. Since the electric field is defined to the be gradient of the potential, the surface of the conductor would not have a constant potential.

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Why electric field lines are perpendicular to surface area?

Why are electric field lines perpendicular on any surface (randomly, sphere, straight line, etc.)? Electric field lines are guaranteed to be perpendicular to a CONDUCTING surface in the electrostatic case. If there is a parallel component at the surface then there will be current flow until an electrostatic configuration is met.

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Why electric field lines are perpendicular to surface plate?

Electric field lines are guaranteed to be perpendicular to a CONDUCTING surface in the electrostatic case. If there is a parallel component at the surface then there will be current flow until an electrostatic configuration is met. Field lines are NOT perpendicular to conductors that are carrying current.

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Why electric field lines are perpendicular to surface waves?

First you need some vectors. If a vector, say a force vector, is making an angle of theta with the surface of an object, then that force will have a perpendicular …

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Why electric field lines are perpendicular to the surface?

Electric flux through a surface is at *maximum* when the electric field is perpendicular to the surface. The whole point of flux is to measure the “total number of field lines” punching through a surface. If the electric field is lying *along* the surface, it isn’t going in or going out and the flux is zero.

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Why are electric field lines perpendicular at a conductor?

  • Because if they are not perpendicular then there will be a component of E along the surface of conductor. Due to this component, electrons on the suface experence an electric force given by F = qE. As electrons are free to move on the surface of conductor so an electric current produces on the surface of conductor.

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A flat charged surface electric field is called?

Electric Field: Parallel Plates. If oppositely charges parallel conducting plates are treated like infinite planes (neglecting fringing), then Gauss' law can be used to calculate the electric field between the plates. Presuming the plates to be at equilibrium with zero electric field inside the conductors, then the result from a charged conducting surface can be used:

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A flat charged surface electric field is formed?

Electric Field, Flat Sheets of Charge. Electric Field: Sheet of Charge. For an infinite sheet of charge, the electric field will be perpendicular to the surface. Therefore only the ends of a cylindrical Gaussian surfacewill contribute to the electric flux .

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A flat charged surface electric field is made?

Electric Field: Sheet of Charge For an infinite sheet of charge, the electric field will be perpendicular to the surface. Therefore only the ends of a cylindrical Gaussian surface will contribute to the electric flux .In this ...

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What represent the surface integral of electric field intensity?

Electric flux.

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Why electric field lines are perpendicular to equipotential surface coverage?

Electric field lines cannot be parallel to the equipotential surface. Because if they are or if they have component along equipotential surface, that means electrical field exists along equipotential surface. And if electric field exists that mean...

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Why electric field lines are perpendicular to equipotential surface properties?

Consider if they are not perpendicular, there will be two components which can cause charge to move along the surface. This means that there is some potential difference which is cannot be true since equipotential surfaces, by definition, should be a surface where the potential is constant accross the surface. Answer verified by Toppr Upvote (0)

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Why electric field lines are perpendicular to equipotential surface waves?

Electric field lines cannot be parallel to the equipotential surface. Because if they are or if they have component along equipotential surface, that means electrical field exists along equipotential surface. And if electric field exists that mean...

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Why is an electric field perpendicular to a gaussian surface?

Gauss law states that electric field on any gaussian surface is due to electric flux related to that surface. As shown in the image the electric flux related to this gaussian surface is due to both q1 and q2 , so calculated electric field will be due to both q1 and q2.

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Why is an equipotential surface perpendicular to the electric field?

Why should an electric field be perpendicular to the equipotential surface? ‘Should’ is an interesting word. Two cases must be considered. The most general case allows for changing electric fields (i.e. Real World). In this case the electric field will NOT (necessarily) be perpendicular to the equipotential surface. In fact the ‘projection’ of the E-field onto any conductive surface will tell us which way the electric charges will be accelerating on this surface. (Think Antenna Design.)

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What is electric field on surface of conductor?

We know that this field has $E = \frac{\sigma}{2\epsilon_0}$ pointing away from it (away and towards the surface of the conductor). We also know that the electric field inside the conductor must be 0; thus the conductor itself must have an electric field of $E = \frac{\sigma}{2\epsilon_0}$ pointing outward to cancel out the incoming field of the charge distribution.

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Electric field intensity equation?

Electric Field Intensity (E) = q/[4πεd 2] NC-1 The intensity of the electric field at any point due to a number of charges is equal to the vector sum of the intensities produced by the separate charges.

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Electric field intensity problems?

Electric Field - Problems and Solution. Problems and solutions on electric fields are presented for high school and college students. More practice problems in electric fields are also provided here. Electric and magnetic fields are vector quantities in physics. These quantities are described both with a magnitude and a direction (angle).

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