Why the electric field just outside the conductor is perpendicular on its' surface?

Saige Streich asked a question: Why the electric field just outside the conductor is perpendicular on its' surface?
Asked By: Saige Streich
Date created: Mon, Feb 22, 2021 6:11 PM

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Those who are looking for an answer to the question «Why the electric field just outside the conductor is perpendicular on its' surface?» often ask the following questions:

👉 Why electric field is perpendicular to surface of conductor?

Here is another intuitive explanation: Imagine for a moment that the electric field was not perpendicular to the surface. That means it has a component along the surface. Now, electric fields exert a force on charges, so now we have a force on the charges in the conductor along the surface of the conductor.

👉 Why are electric field lines perpendicular to the surface of a conductor?

Now, suppose electric field lines are not perpendicular to the local surface of the conductor . Then electric field will have some component parallel to the surface.

👉 Why are electric field lines perpendicular to the surface of the conductor?

First you need some vectors. If a vector, say a force vector, is making an angle of theta with the surface of an object, then that force will have a perpendicular component Fsin thetha and a tangential or parallel component (parallel to the surfa...

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If it isn't perpendicular, the charges would be redistributed because there would be force component tangential to the surface. In other words, the charges would move to a new equilibrium position, in which the electric field IS perpendicular to the surface.If it isn't perpendicular, the charges would be redistributed because there would be force component tangential to the surface. In other words, the charges would move to a new equilibrium position, in which the electric field IS perpendicular to the surface.If it isn't perpendicular, the charges would be redistributed because there would be force component tangential to the surface. In other words, the charges would move to a new equilibrium position, in which the electric field IS perpendicular to the surface.If it isn't perpendicular, the charges would be redistributed because there would be force component tangential to the surface. In other words, the charges would move to a new equilibrium position, in which the electric field IS perpendicular to the surface.

For conductors, the electric field perpendicular to its surface and no field exist within the conductor. As a result the equipotential lines are found near the surface.

Meaning, if you get any charge from infinity to any point on this surface, equal amount of work is done. Thus if you find this locus it is always perpendicular because of the fact that electric field lines actually represent the gradient in potential.

Now, suppose electric field lines are not perpendicular to the local surface of the conductor. Then electric field will have some component parallel to the surface. This component will give potential difference dV=-E (parallel).dl between the nearby points. Then, the surface is not equipotential surface.

Basically they say that the e-field inside the conductor is zero, as we all know, and then they find the flux through a gaussian cylinder with its axis oriented perpendicular to the surface. Gauss' law tells us that the flux exiting a gaussian surface is proportional to the enclosed charge.

The electric field just outside the surface of a conductor (E2) is normal to the surface. There can be no tangential component. If there were a tangential component, the electrons would move along the surface until it was gone.

The electric field is zero inside a conductor. Just outside a conductor, the electric field lines are perpendicular to its surface, ending or beginning on charges on the surface. Any excess charge resides entirely on the surface or surfaces of a conductor. Accordingly, what is a charged conductor?

Which one of the following statements about a charged conductor in electrostatic equilibrium is true? (1) The electric field just outside the surface is zero (2) The electric field just inside the surface is perpendicular to the surface (3) The electric charge is distributed uniformly throughout the volume of the conductor (4) The electric field just outside the surface is perpendicular to the surface

As we know that the electrostatic field inside the conductor is zero, therefore no work is done in moving a small test charge, within the conductor and on its surface. We find there is no potential difference between the two points inside or on the surface, which implies the electrostatic potential is constant throughout.

Now, suppose electric field lines are not perpendicular to the local surface of the conductor . Then electric field will have some component parallel to the surface. This component will give potential difference d V = − E (p a r a l l e l). d l between the nearby points. Then, the surface is not equipotential surface. So, for surface to be equipotential surface for static charge distribution the field lines at the surface are perpendicular to the surface.

The electric field is zero inside a conductor. Just outside a conductor, the electric field lines are perpendicular to its surface, ending or beginning on charges on the surface. Any excess charge resides entirely on the surface or surfaces of a conductor.

Your Answer

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Is electric field always perpendicular at a surface point?

Assuming that that electric field is not perpendicular to the surface, then there must be a component of the electric field that is parallel to the surface. Since the electric field is defined to the be gradient of the potential, the surface of the conductor would not have a constant potential.

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Why electric field lines are perpendicular to the surface?

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Why are electric field lines perpendicular at a conductor?

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Why electric field lines are perpendicular to equipotential surface coverage?

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Why is an electric field perpendicular to a gaussian surface?

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What is electric field on surface of conductor?

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