Why there is an electric field inside a non-conducting sphere found?

Kenya Funk asked a question: Why there is an electric field inside a non-conducting sphere found?
Asked By: Kenya Funk
Date created: Mon, Jun 21, 2021 11:47 AM

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Those who are looking for an answer to the question «Why there is an electric field inside a non-conducting sphere found?» often ask the following questions:

👉 Why is there no electric field inside a conducting sphere?

What is the electric field inside a non conducting shell? The electric field will be zero inside a spherical shell no matter if it is conducting or nonconducting, because according to Gauss’s law Φ=Qencϵ, where Φ is the electric flux thru the Gaussian surface, and Qenc is the charge inside the Gaussian surface.

👉 Why there is an electric field inside a non conducting sphere?

Why there is an electric field inside a non conducting sphere? As there is no charge inside the cavity, no charge is enclosed by Gaussian sphere, so electric flux is zero, hence electric field is zero. Can Charge exist inside a non conducting medium? Inside a uniformly charged non-conducting sphere, charge is uniformly distributed.

👉 Can an electric field exist inside a conducting sphere?

The reason is, in case of conducting sphere electric field do not penetrate inside the sphere so there is no variation of electric field inside a conducting sphere, so work done in moving an object in a closed path is zero inside a conducting sphere and that's why electric potential

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Therefore electric field inside a uniformly charged non- conducting spherical shell is zero. What is the electric field inside a non conducting shell? The electric field will be zero inside a spherical shell no matter if it is conducting or nonconducting, because according to Gauss’s law Φ=Qencϵ, where Φ is the electric flux thru the Gaussian surface, and Qenc is the charge inside the Gaussian surface.

Consider a charged non conducting solid sphere of uniform charge density, and it as hole of some radius at the centre. Now suppose I apply Gauss law. As there is no charge inside the cavity, no charge is enclosed by Gaussian sphere, so electric flux is zero, hence electric field is zero.

The electric field intensity inside a cavity is zero, even if the shell is not spherical and has any irregular shape. Take a closed loop such that a part of it is inside the cavity along a field line while the rest is inside the conductor. Hence, electric field is zero, whatever is the shape. How is charge distributed on a sphere?

From there, a simple application of Gauss's law, ... why an off-center point inside the sphere has zero charge. The fact that the sphere is "spherically symetric and static" is quite obvious but the OP was asking specifically how does this imply the zero charge. Gauss's law only describes electric field originating in an enclosed region – and again, it's obvious that an empty patch of space wouldn't generate any electric field. $\endgroup$ – m93a May 30 '18 at 7:53. 1 $\begingroup$ @m93a ...

Also, the electric field inside a conductor is zero. (This, also, is because of the free movement of charges. If there was a net electric field inside, the charges would rearrange because of it, and cancel it out.) Therefore, all the charge has to lie on the surface of the conductor.

“Electric field intensity due to charge non-conducting solid sphere by gauss theorem”: Case(1): outside of sphere Consider a non conducting sphere of centre 0 and radius R. On charging this sphere, the charge is uniformly distributed in whole volu...

But precisely because the electric field inside the sphere is zero, you won't have to do any work. Thus the potential remains the same inside the sphere and equal to the potential of the charge at the outer boundary of the sphere. You only have to do work till the outer boundary of the sphere.

In many introductory books on electrostatics, you can find the statement that the field inside a conducting shell is zero if there are no charges within the shell. For example, if we place an uncharged conducting sphere in a uniform electric field we would get something like this:

The electric field inside a sphere of uniform charge is radially outward (by symmetry), but a spherical Gaussian surface would enclose less than the total charge Q. The charge inside a radius r is given by the ratio of the volumes: The electric flux is then given by. and the electric field is. Click to see full answer.

However, when the charge distribution becomes non-uniform, the enclosed charge is still zero, implying that the electric field is still zero. However, if all the charge on the sphere is moved to one side, there should be an electric field directed from one hemisphere to the other. I'm wondering how this application of Gauss's law here is wrong ...

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Electric field within the cavity of a conducting sphere?

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Consider a charged non conducting solid sphere of uniform charge density, and it as hole of some radius at the centre. Now suppose I apply Gauss law. As there is no charge inside the cavity, no charge is enclosed by Gaussian sphere, so electric flux is zero, hence electric field is zero. But this is not true according to sources like this, textbook ...

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Why is the electric field in a conducting sphere zero?

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Why electric field inside a sphere is zero?

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Why is electric field zero inside s sphere?

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Electricity - why the potential inside a solid conducting sphere is non zero while the electric field inside is zero?

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